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Metode regulasi falsi

1. Metode Regulasi Falsi 2. Metode Biseksi (Bisection) 3. Contoh : Xn : 2.5 Xn+1 : 2.6 4. Penyelesaian Berdasarkan Algoritma penyelesaian di atas maka diperoleh : 5. Maka…
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  • 1. Metode Regulasi Falsi
  • 2. Metode Biseksi (Bisection)
  • 3. Contoh : Xn : 2.5 Xn+1 : 2.6
  • 4. Penyelesaian Berdasarkan Algoritma penyelesaian di atas maka diperoleh :
  • 5. Maka diperoleh tabel
  • 6. Apakah f(xn) dan f(x*) sama tanda? Jika sama tanda maka x* menggantikan xn, sedangkan jika berbeda tanda maka x* menggantikan xn+1. Terlihat dari tabel di atas, f (xn) = -0.875 dan f (x*) = -0.015 sama tanda, maka x* = 2.57 menggantikan xn = 2.5.
  • 7. Apakah | f (x*)| ≤ 0.005? Jika ya, maka x* = 2.57 merupakan solusi dari persamaan non linier tersebut, jika tidak, ulangi langkah 2 dengan xn = 2.57 dan xn+1 = 2.6. Dikarenakan | f (xmid)| = 0.015 > 0.005 maka lakukan iterasi dari tabel di atas
  • 8. Hasil
  • 9. Latihan Dengan menggunakan metode biseksi dan regulasi falsi dengan e = 0.005, cari solusi dari: 1. 2.
  • 10. Terima Kasih
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